4y-3/y^2+1=4y/4

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Solution for 4y-3/y^2+1=4y/4 equation: 



4y-3/y^2+1=4y/4

We move all terms to the left:

4y-3/y^2+1-(4y/4)=0



Domain of the equation: y^2!=0

y^2!=0/

y^2!=√0

y!=0

y∈R



We add all the numbers together, and all the variables

4y-3/y^2-(+4y/4)+1=0

We get rid of parentheses

4y-3/y^2-4y/4+1=0

We calculate fractions

There is no solution for this equation

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